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LeetCode 第二道题: Add Two Numbers,难度简单。
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. Example: Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 81 Explanation: 342 + 465 = 807.
1 /**
2 * Definition for singly-linked list.
3 * public class ListNode {
4 * public int val;
5 * public ListNode next;
6 * public ListNode(int x) { val = x; }
7 * }
8 */
9 public class Solution {
10 public ListNode AddTwoNumbers ( ListNode l1 , ListNode l2 ) {
11
12 ListNode ret = null ;
13 ListNode l3 = null ;
14
15 var add = 0 ;
16 while ( l1 != null && l2 != null )
17 {
18 var val = l1 . val + l2 . val + add ;
19 add = val / 10 ;
20 val = val % 10 ;
21
22 var node = new ListNode ( val );
23 if ( l3 == null )
24 {
25 l3 = node ;
26 }
27 else
28 {
29 l3 . next = node ;
30 l3 = node ;
31 }
32
33 if ( ret == null )
34 {
35 ret = node ;
36 }
37
38 l1 = l1 . next ;
39 l2 = l2 . next ;
40 }
41
42 while ( l1 != null )
43 {
44 var val = l1 . val + add ;
45 add = val / 10 ;
46 val = val % 10 ;
47
48 var node = new ListNode ( val );
49 if ( l3 == null )
50 {
51 l3 = node ;
52 }
53 else
54 {
55 l3 . next = node ;
56 l3 = node ;
57 }
58
59 l1 = l1 . next ;
60 }
61
62 while ( l2 != null )
63 {
64 var val = l2 . val + add ;
65 add = val / 10 ;
66 val = val % 10 ;
67
68 var node = new ListNode ( val );
69 if ( l3 == null )
70 {
71 l3 = node ;
72 }
73 else
74 {
75 l3 . next = node ;
76 l3 = node ;
77 }
78
79 l2 = l2 . next ;
80 }
81
82 if ( add > 0 )
83 {
84 var node = new ListNode ( add );
85 if ( l3 == null )
86 {
87 l3 = node ;
88 }
89 else
90 {
91 l3 . next = node ;
92 l3 = node ;
93 }
94 }
95
96 return ret ;
97 }
98 }
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